Analytical Chemistry The Chemical Analysis Treatment of analytical data Chemical Calculations
The
Chemical Analysis
Chemical analysis is divided into two main methods (classic
and instrumental methods).
Classic Methods of Analysis:
Classic methods provide accurate and precise results but require
relatively large quantities of sample and long time.
They involve gravimetry (based on weight) and
volumetry or titrimetry (based on volume)
Instrumental Methods of Analysis:
Instrumental methods based on using electric instruments.
They are generally more sensitive, selective and rapid.
They involve electrochemical methods, spectrochemical methods,
graphimetric methods, …..etc.
Treatment of analytical data
Units of
Measure
Compare these instructions:
“Transfer 1.5 of your sample to a 100 volumetric flask, (incomplete
since the units of measurement are not stated).
“Transfer 1.5 g of your sample to a 100-mL volumetric flask.
(complete)
Measurements usually consist of a unit and a number.
The system international units, (SI units).
Measurement |
Unit |
Symbol
|
Mass |
Kilogram |
Kg
|
Volume |
Liter |
L |
amount of substance |
Mole |
Mol |
UNIT CONVERSIONS
Unit conversions
based on proportional rules, for example convert 5 ml to liter ?
1 Liter =
1000 ml
X liter =
5 ml
X = (1 l
x 5 ml ) / 1000 ml = 0.005 liter
or 5x10-3 liter
Convert 34.5 mg to g
Science 1 g
= 1000 mg
x g = 34.5
mg
For simplicity the very large or very small measurements, for
example, a mole contains 602,000,000,000,000,000,000,000 particles, and some analytical
techniques can detect as little as 0.000000000000001 g of a compound.
We use scientific
notation; thus,
a mole contains 6.02 ´ 1023 particles, and
the stated mass is 1 ´ 10–15 g.
Sometimes it is preferable to use prefixes (like kilo, milli, micro,……. ).
Chemical
Calculations
Atomic
Weight, Molecular Weight and Equivalent Weight
Atomic Weight (Aw)
An atom's mass can be found by summing the
number of protons and neutrons. It is
measured in atomic mass units (amu).
For example, the atomic weight of Na is 23
amu,
Molecular Weight (M.wt)
Simply add the
individual mass of each atom in the compound.
For example, the molecular mass of glucose (C6H12O6)
is (6x12+12x1+6x16) = 180 amu,
The Moles
The mole is equal to the chemical formula
mass, except that the unit is grams per mole instead of amu.
One mole of any element is the atomic mass
of that element expressed as a weight in grams.
One mole of any compound is the molecular
mass of that compound expressed as a weight in grams.
Molar Weight (Mol.wt)
The molar weight (or molar mass) is exactly the same as the atomic weight of an element, or the molecular weight of a compound.
For example, the atomic weight of oxygen is 16.00 amu, so its molar mass
is 16.00 g/mol and the atomic weight of Fe = 55.8 amu, so its molar mass
is 55.8 g/mol,
For species with more than one element, (such as compounds), we simply add the individual atomic mass of each element in the compound (found on the periodic table) to obtain the molar mass of the compound.
In general, Molar mass is the mass (in
grams) of one mole of a substance.
For example, the formula mass of glucose (C6H12O6) is (6x12+12x1+6x16) = 180 amu, so its molar
mass is 180 g/mol.
Another example, sulfur trioxide gas is made up of sulfur and oxygen, whose atomic weights are 32.06 and 16.00 respectively.
NaCl =
58.5 g/mol, Na2CO3
= 106 g/mol,
H2SO4
= 98 g/mol, NaOH = 40 g
…..etc
Aluminium carbonate, for example, contains
aluminium, carbon, and oxygen. To find the molar mass, we have to be careful to
find the total number of atoms of each element. Three carbonate ions each
containing three oxygen atoms gives a total of nine oxygens. The atomic weights
of aluminium and carbon are 26.98 and 12.01 respectively.
The Equivalent Weight (Eq. Wt)
Eq.Wt =
Where F
is equivalent number and it is defined
as following :-
·
Number of H+ in acids
For example HCl
→ H+ + Cl- F = H+ = 1
H2SO4 → 2H+ + SO42- F = H+ = 2
CH3COOH → H+
+ CH3COO- F = H+ = 1
·
Number of
Ba(OH)2 → Ba2+ + 2OH- F = 2
·
The equivalent (or charge) of acidic or basic part in a
salt.
Na2CO3 →
2Na + + CO32-
F = 2
· Number of electrons that gain or loss in an oxidation–reduction reaction, or the change in oxidation state (loss means increase and gain means decrease)
Some rules on oxidation number
Except in hydrides (e.g. NaH) hydrogen always is +1, H1+
Except in peroxides (e.g. H2O2), oxygen always is -2, O2-
Alkaline metals, group IA, (Li, Na, K, Rb, Cs) are in +1
Alkali earth metals ,IIA, (Mg, Ca, Sr, Ba, ..etc) are in +2
For neutral compounds, the total or sum equal zero, for example NaCl = 0, mean that Na+ + Cl- = +1 + -1 = 0
H2C2O4 2H + 2C +4O = 2(+1) +2(+3) + 4(-2) = +2+6-8= 0
For polyatomic ions, the sum equals the charge for example MnO4- = +7-8 = -1 and in C2O42- 2C +4O = +2(+3) + 4(-2) = +6-8= -2
Question
Calculate the oxidation number of the following:
C in CO, CO2, H2C2O4
and CO3--? N
in NO, NH3, and HNO3? S in SO2
SO42-? Mn in
KmnO4? Cr in Cr2O72-?
For example,
in the following reaction between Fe3+ and oxalic acid, H2C2O4,
2Fe3+(aq) + H2C2O4 (aq) + 2H2O(l) ↔ 2Fe2+(aq) + 2CO2(g) +2H3O+(aq)
Iron
is reduced since its oxidation state changes from +3 to +2.
Oxalic
acid, on the other hand, is oxidized since the oxidation state for carbon
increases from +3 in H2C2O4 to +4 in CO2.
So,
the Eq.Wt of Fe is Mol.wt of Fe/1 = 56/1 = 56
And the Eq.Wt of H2C2O4, is Mol.wt of H2C2O4,/2 (90/2 = 45)
Question
Calculate the equivalent weight (Eq. wt.) of
Na, Fe and Sn according to the following equations ?
Na
+ H2O → NaOH +
H2
2FeCl3 + SnCl2 → 2FeCl2 + SnCl4
Substances |
Chemical formula |
Equivalent number (F) |
Hydrochloric acid |
HCl |
1 |
Nitric acid |
HNO3 |
1 |
Acetic acid |
CH3COOH |
1 |
Sulfuric acid |
H2SO4 |
2 |
Oxalic acid |
H2C2O4 |
2 |
Phosphoric acid |
H3PO4 |
3 |
Sodium hydroxide |
NaOH |
1 |
Potassium hydroxide |
KOH |
1 |
Calcium hydroxide |
Ca(OH)2 |
2 |
Barium hydroxide |
Ba(OH)2 |
2 |
Sodium bromide |
NaBr |
1 |
Potassium chloride |
KCl |
1 |
Ferric chloride |
FeCl3 |
3 |
Magnesium sulfate |
MgSO4 |
2 |
Sodium carbonate |
Na2 CO3 |
2 |
Sodium chloride |
NaCl |
1 |
Magnesium chloride |
MgCl2 |
2 |
Ammonium chloride |
NH4Cl |
1 |
Potassium bicarbonate |
K(HCO3) |
1 |
Silver nitrate |
AgNO3 |
1 |
Ammonium chloride |
NH4Cl |
1 |
Copper (II) sulfite |
CuSO3 |
2 |
Calcium nitride |
Ca3N2 |
6 |
Exercise
Calculate the equivalent weight (Eq.wt) for each compound in the above table ?
READING MORY
INTRODUCTION TO ANALYTICAL CHEMISTRY
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